#include<stdio.h>
main()
{
int array[100], search, c, n, count = 0;
printf("Enter the number of elements in array\n");
scanf("%d",&n);
printf("Enter %d numbers\n", n);
for ( c = 0 ; c < n ; c++ )
scanf("%d",&array[c]);
printf("Enter the number to search\n");
scanf("%d",&search);
for ( c = 0 ; c < n ; c++ )
{
if ( array[c] == search )
{
printf("%d is present at location %d.\n", search, c+1);
count++;
}
}
if ( count == 0 )
printf("%d is not present in array.\n", search);
else
printf("%d is present %d times in array.\n", search, count);
return 0;
}
Output:
Enter the number of elements in array
4
Enter 4 numbers
8
5
8
7
Enter the number to search
8
8 is present at location 1.
8 is present at location 3.
8 is present 2 times in array
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